Question

The two dot plots below compare the forearm lengths of two groups of schoolchildren:

Answer 1

According to given text data

Average of both groups

A:-

• 10(3)+11(4)+12(3)/10
• 30+44+36/10
• 66+44/10
• 110/10
• 11

B:-

• 9(3)+5(10)+11(2)/10
• 27+50+22/10
• 49+50/10
• 99/10
• 9.9

Group A has bigger average

Answer 2

Answer:

Group A, because seven children have a forearm length longer than 10 inches

Step-by-step explanation:

Create the dot plots based on the given information (please see attached images).

Group A = blue dots

Group B = red dots

From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length.  This is because 7 children have a forearm length of longer than 10 inches.

To calculate the average forearm length, sum all data values and divide by the total number of data values.

$\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11$

$\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9$

Thus proving that Group A has the longer average former length.