To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
Area = 168m^2
Step-by-step explanation:
Area of triangle = 1/2×base×height
Area = 1/2bh
= 1/2(8+16)(14)
= 168m^2
Answer:
40%
Step-by-step explanation:
Ok so my brain is sorta not working but it said "hey! 20 divided by 2 is 10!"
So I was like ight and divided 80 by 2 to to get 40%.
Hope this helps.
Answer:
hello :
the area is : A= w ×l ... w : the width l : the length
A = 323 l = 19 w ?
l = A/w
l = 323/ 19
l = 17 feet
Hope This Helps
#1: "AD" is congruent to "BC" | given
