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2 years ago

14

What is the volume of a cylinder of radius 3.5m and height 12m ?

2 answers:

boyakko [2]2 years ago

5 0

Answer:

426m²

<u>Step-by-step explanation:</u>

Given ;

radius = 3.5m , hieght = 12m

<u>Volume of cylinder = π2²h </u>

22/7 × ( 3.5 )² × 12
22/7 × ( 7/2 )² × 12
22/7 × 7/2 × 7/2 × 12
462m²

Volume of the cylinder is 426m².

Savatey [412]2 years ago

4 0

Answer:

462

Step-by-step explanation:

Base=π × r²

=> π × 3.5²

=>38.48

Volume:

Base times height

=>38.48 x 12

=>461.81

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GEOMETRY , FIND THE AREA OF A REGULAR POLYGON!! BRAINLIEST GIVEN!! BOGUS ANSWERS BLOCKED

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To find the area of a regular figure,the formula would be:

s^2(n)/4tan (180/n)

where
s is the length of any side
n is the number of sides

In this case:
12^2(6)/4tan (180/6)
=144/4tan(30)
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≈374.1 in^2 (correct to the nearest tenth)

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3 years ago

Three students wrote equations on their dry erase boards.

tiny-mole [99]

Answer:

13/20 = 65%

Step-by-step explanation:

1/4 = 25%

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3 years ago

A student solved this problem by working backwards.

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3 years ago

Sample annual salaries (in thousands of dollars) for employees at a company are listed. (a) Find the sample mean and sample s

Helen [10]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

The value is attached in the image file please find it.

In point a:

First, we calculate the find the mean,

Formula:

$\to Mean (\bar{x}) = \frac{( \sum x)}{n}$

$=\frac{540}{13}\\\\ = 41.54$

To calculate the standard deviation, subtract the mean value from all observations then square its value:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{339.2308}{13-1}}$

$= \sqrt{ \frac{339.2308}{12}}\\\\= \sqrt{28.269}\\\\=5.31$

please find attached file

In point b:

New $x_i = 1 x_i + 0.05 x_i = 1.05 x_i$

Calculate new mean:

$\to \bar{x} = \frac{\sum x}{n} \\$

$=\frac{567}{13} \\\\= 43.62$

calculating the standard deviation:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{374.0022}{13-1}}$

$= \sqrt{ \frac{374.0022}{12}}\\\\= \sqrt{31.16}\\\\=5.58$

please find attached file

In point C:

Calculate new mean:

$\to \bar{x} = \frac{\sum x}{n} \\$

$=\frac{47.25}{13} \\\\= 3.46$

calculating the standard deviation:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{2.5975}{13-1}}$

$= \sqrt{ \frac{2.5975}{12}}\\\\= \sqrt{0.216}\\\\=0.46$

please find attached file

In point d:

for b,

New $\bar{x}= 1.05 \bar{x}= 1.05(41.54) =43.62$

New $s= 1.05s= 1.05(5.31)=5.57$

for c,

New $\bar{x}= \frac{ \bar{x}}{12}= \frac{41.54}{12} = 3.46$

New $s = \frac{s}{ 12} = \frac{5.31}{12}= 0.44$

4 0

4 years ago

Anyone help? I haven’t been in school bc I was sick pls help

Ratling [72]

2/3 or 0.6 repeating is the answer

5 0

3 years ago

Read 2 more answers