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Alenkasestr [34]
2 years ago
13

65. If the diameter of the sphere is halved, what will be the difference in volume?

Mathematics
1 answer:
Murrr4er [49]2 years ago
7 0

Answer:

Hi there !

  • A. 1/8 of the original volume
  • 24 is the mode

<h2>Step-by-step explanation:</h2>

<h3>Question 1 :-</h3>

LET RADIUS OF SPHERE= R

VOLUME OF SPHERE= ( \frac{4}{3})\pi \:  {r}^{3}

WHEN RADIUS IS HALVED RADIUS IF SPHERE=R/2

VOLUME= ( \frac{4}{3} )\pi( \frac{r}{2})^{3} = {(4/3)πR^3}/8

THE VOLUME WILL BECOME 1/8 TH OF THE ORIGINAL VOLUME.

<h2>Question 2 :-</h2>

Wehave,

Mode+2×Mean=3×Median

⇒Mode=3×Median−2×Mean

Given : Mean=21 and Median=22

Putting the given values, we get

Mode=3×22−2×21=66−42=24.

Hope it helps u....

Stay safe, stay healthy and blessed

Have a great day !

Thank you

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See answers and explanations below (along with a visual graph)

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The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

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Approximate

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Read more about composite functions at:

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