Question

65. If the diameter of the sphere is halved, what will be the difference in volume?

Answer 1

Answer:

Hi there !

• A. 1/8 of the original volume
• 24 is the mode

Step-by-step explanation:

Question 1 :-

LET RADIUS OF SPHERE= R

VOLUME OF SPHERE= $( \frac{4}{3})\pi \: {r}^{3}$

WHEN RADIUS IS HALVED RADIUS IF SPHERE=R/2

VOLUME= $( \frac{4}{3} )\pi( \frac{r}{2})^{3}$ = {(4/3)πR^3}/8

THE VOLUME WILL BECOME 1/8 TH OF THE ORIGINAL VOLUME.

Question 2 :-

Wehave,

Mode+2×Mean=3×Median

⇒Mode=3×Median−2×Mean

Given : Mean=21 and Median=22

Putting the given values, we get

Mode=3×22−2×21=66−42=24.

Hope it helps u....

Stay safe, stay healthy and blessed

Have a great day !

Thank you