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2 years ago

65. If the diameter of the sphere is halved, what will be the difference in volume?

Mathematics

1 answer:

Murrr4er [49]2 years ago

7 0

Answer:

Hi there !

A. 1/8 of the original volume
24 is the mode

<h2>Step-by-step explanation:</h2>

<h3>Question 1 :-</h3>

LET RADIUS OF SPHERE= R

VOLUME OF SPHERE= $( \frac{4}{3})\pi \: {r}^{3}$

WHEN RADIUS IS HALVED RADIUS IF SPHERE=R/2

VOLUME= $( \frac{4}{3} )\pi( \frac{r}{2})^{3}$ = {(4/3)πR^3}/8

THE VOLUME WILL BECOME 1/8 TH OF THE ORIGINAL VOLUME.

<h2>Question 2 :-</h2>

Wehave,

Mode+2×Mean=3×Median

⇒Mode=3×Median−2×Mean

Given : Mean=21 and Median=22

Putting the given values, we get

Mode=3×22−2×21=66−42=24.

Hope it helps u....

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<h3>Pythagoras theorem</h3>

Pythagoras theorem is used to show the relationship between the sides of a right angled triangle. It is given by:

Hypotenuse side² = Adjacent side² + Opposite side²

Let x represent the distance from the satellite to the Earth's horizon

Hence:

x² = 6370² + 600²
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The distance from the satellite to the Earth's horizon is 6398 km

Find out more on Pythagoras theorem at: brainly.com/question/343682

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Step-by-step explanation:

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