Answer:
1) c. 10
2) a. 1 and 18
3) d. 17
4) I think it's actually 12 but I don't know
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Remember that percent means parts out of 100
x/100
discount is the decrease
so we divide the decrease by the original total and get
100/5775=0.0173
convert to fraction
0.0173/1
make bottom number 100
multiply by 100/100
1.73/100=1.73%
round
2%
They are all quadrilaterals <span />
