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drek231 [11]
1 year ago
12

Solve the propotions

Mathematics
1 answer:
cluponka [151]1 year ago
8 0

Answer:

8

Step-by-step explanation:

8/12 simplifyed = 2/3

8 divided by 4 = 2

12 divided by 4 = 3

Hope this helps! :>

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What does y equal??????
tangare [24]

Answer:

118 degrees

Step-by-step explanation:

I think you it's the same, because it a just rotation of the shape.

5 0
2 years ago
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Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide
hichkok12 [17]

Answer:

A  99% confidence interval  will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

  The  95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

From the above equation we see that

          E \ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Here  Z_{\frac{\alpha }{2} }  is the critical value of the half of the level of significance and this value  increase as the confidence level increase

Now if a  99% confidence level is  used , it then means that the value of  

 Z_{\frac{\alpha }{2} }  will increase, this in turn will increase  the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval  will be wider than a 95% confidence interval

5 0
3 years ago
Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
2 years ago
For which independent value do the equations generate the same dependent value? y1=6x-16 , y2=3x-10
Nikitich [7]
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3 years ago
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melomori [17]

Answer:

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8 0
3 years ago
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