Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
First change them to the same denominator....
2×3 6
__ = __
5×3 15
1×5 5
__ = __
3×5 15
6/15+ 5/15= 11/15.
So the sum is 11/15
The sum of all the angles of any quadrilateral is 360 degrees
115 + 97 + 58 + missing angle = 360
missing angle = 90 degrees
Hope that helps!
The equation of a line is written as y =Mx + b, where m is the slope and b is the y intercept, which is the y value when x = 0.
You are told the slope is -1/4, so replace m with -1/4. You are also given the point (0,0) which means when x is 0, y is also 0, so replace b with 0.
The equation becomes y= -1/4x + 0
Because y is 0 you aren’t adding anything to the equation so you can remove it from the equation.
Answer is y = -1/4x
