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frutty [35]
2 years ago
8

A box in the shape of a rectangular prism has a width that is 5 inches greater than the height and a length that is 2 inches gre

ater than the width. Write a polynomial expression in standard form for the volume of the box. Explain the meaning of any variables used.
Mathematics
1 answer:
aliina [53]2 years ago
7 0

The volume of the rectangular prism can be express in standard polynomial as follows:

x³ + 12x² + 35x

<h3>How to find the volume of a rectangular prism?</h3>

volume of a rectangular prism = lwh

where

  • l = length
  • w = width
  • h = height

Therefore,

let

height = x

width = x + 5

length = x + 5 + 2 = x + 7

Therefore,

volume = x(x + 5)(x + 7)

volume = x(x² + 7x + 5x + 35)

volume = x(x² + 12x + 35)

volume = x³ + 12x² + 35x

learn more on volume here: brainly.com/question/2005063

#SPJ1

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Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

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