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2 years ago

HELPPPPP PLZZZZZZZZZZ

Mathematics

2 answers:

lianna [129]2 years ago

6 0

Answer:

a. one

b. three

c. eleven

Step-by-step explanation:

just count the dots ??

SOVA2 [1]2 years ago

6 0

A.) 1 student
b.) 3 students
c.) 11 students

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There were 300 people at the dance.tickets cost $5 for visitors and $3 for students. the total ticket sales were $1100. how many

frez [133]

There were 200 students that attend the dance.

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3 years ago

The length of a rectangle is 5 more than 3 times the width. Write and solve an equation to find the width (w) if the length is 1

GenaCL600 [577]

Answer:

Length = 42.5 cm

Step-by-step explanation:

length of rectangle = 5 + 3w

So l = 5 + 3w where w = 12.5

Equation:

L = 5 + 3(12.5)

Solving the Equation:

L = 5 + 3(12.5)

L = 5 + 36 + 1.5

L = 42.5

Length: 42.5 cm

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2 years ago

Elaborar 10 ejemplos de números decimales con tres términos por ejemplo : 3.99+0.000345+322.99

maksim [4K]

Answer:

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1 year ago

Translate and solve the algebraic statement for the given number below:

xenn [34]

I think the answer is -7

8 0

2 years ago

Dora calculated the mean absolute deviation for the data set 35, 16, 23, 42, and 19. Her work is shown below.

Crazy boy [7]

Answer:

The calculation in step 3 is wrong

Step-by-step explanation:

1) The mean of a dataset is given by the sum of the values of the dataset divided by the number of values.

In this problem, the dataset is

35, 16, 23, 42, 19

And the number of data is

N = 5

So the mean is

$\bar x=\frac{35+16+23+42+19}{5}=27$

So, step 1 is correct.

The absolute deviation of a value in the dataset is the absolute value of its difference from the mean value:

$\sigma_i = |x_i-\bar x|$

Since here the mean value is

$\bar x=27$

Then for each of the values in this dataset, we have:

$\sigma_{1}=|35-27|=8\\\sigma_{2}=|16-27|=11\\\sigma_{3}=|23-27|=4\\\sigma_{4}=|42-27|=15\\\sigma_{5}=|19-27|=8$

So calculations in step 2 are also correct.

The mean absolute deviation is given by the sum of the absolute deviations for each data divided by the number of values in the dataset.

Therefore in this problem, it is:

$\bar \sigma = \frac{\sum \sigma_i}{N}=\frac{8+11+4+15+8}{5}=9.2$

While the result reported by Dora is 9.5: therefore, this step is not correct.

5 0

2 years ago

Read 2 more answers