The rate of change is 1/2
Because it’s the constant and whatever x is, it would always multiply by 1/2
Answer:
11 mm, 21 mm, and 16 mm.
Step-by-step explanation:
since 11+21>16, 11+ 16>21>11, You can form a triangle with 11,21,16
No. The whole numbers are the natural numbers (counting numbers, 1, 2, 3...), but starting with zero instead of one. -1 is an integer but not a whole number.
Step-by-step explanation:
For a quadratic equation y = ax² + bx + c, the vertex (the maximum or minimum point) is at x = -b/(2a).
1) y = -0.5t² + 2t + 38
The maximum is at:
t = -2 / (2 × -0.5)
t = 2
The maximum height is:
y = -0.5(2)² + 2(2) + 38
y = 40
The coordinates of the vertex are (2, 40). That means the missile reaches a maximum height of 40 km after 2 minutes.
2) y = -4.9t² + 12t + 1.6
The maximum is at:
t = -12 / (2 × -4.9)
t = 1.22
The maximum height is:
y = -4.9(1.22)² + 12(1.22) + 1.6
y = 8.95
The coordinates of the vertex are (1.22, 8.95). That means the missile reaches a maximum height of 8.95 m after 1.22 seconds.
3) y = -0.04x² + 0.88x
The maximum is at:
x = -0.88 / (2 × -0.04)
x = 11
The maximum height is:
y = -0.04(11)² + 0.88(11)
y = 4.84
The maximum height of the tunnel is 4.84 meters.
The maximum width is when y = 0.
0 = -0.04x² + 0.88x
0 = -0.04x (x − 22)
x = 22
The maximum width is 22 feet.
Answer:
Step-by-step explanation:
The straight line equation is:
y = m*x + b Where m is the slope of the line and b the intercept with y-axis, in our case y is the depth of the tank and x (time in lapsus of 3 hours).
The slope m = ( y₂ - y₁ ) / (x₂ - x₁)
We have point A ( 3 , 8 ) and point B ( 6 , 7 )
m = ( 6 - 3 ) / (7 - 8 ) m = -3
We see that each 3 hours time-depth decreases 1 in.
Then to find the depth at the beginning of x-axis
At noon 12 tank was 9 inches, three hours before at 9 in the morning the depth was 10 inches and:
9 in the morning 10
6 in the morning 11
3 in the midnight 12
12 in the night 13
Then 13 is the intercept with y-axis
then the equation is:
h = - 3*x + 13
Note x is time in lapsus of 3 hours
