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Lelechka [254]
2 years ago
11

Write the equation of a circle in standard form for the following:

Mathematics
1 answer:
max2010maxim [7]2 years ago
3 0
<h2><u>Circle Equations</u></h2>

<h3>Write the equation of a circle in standard form for the following:</h3><h3>x² − 14x + 49 + y² + 4y = 0</h3>

To write the general form of a circle into standard form, use the formula

<em>(x - h)² + (y - k)² = r²</em>

Where,

<u>(h, k)</u> is the center; and

<u>r</u> is the radius

To transform general form to standard form, group the terms that has the same variables. Replace 0 with the constant term.

  • x² - 14x + 49 + y² + 4y = 0
  • (x² - 14x) + (y² + 4y) = -49

Next step is to complete the square of each equation inside the parentheses.

  • (x² - 14x) + (y² + 4y) = -49
  • (x² - 14x - 49) + (y² + 4y + 2) = -49 - 49 + 2

Then factor each equation inside the parentheses.

  • (x² - 14x - 49) + (y² + 4y + 2) = -49 - 49 + 2
  • (x - 7)² + (y + 2)² = √2
  • (x - 7)² + (y + 2)² = 4

<u>Answer:</u>

  • The standard form of the circle is <u>(x - 7)² + (y + 2)² = 4</u>.

Wxndy~~

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Answer:

Part 1) sin(B)=\frac{21}{29}

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Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

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