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ira [324]
3 years ago
6

Which of the following is a solution of x2 + 4x + 10?

Mathematics
2 answers:
Sloan [31]3 years ago
4 0

Answer:

x=2+-i \sqrt{6}

Step-by-step explanation:

x^2 + 4x + 10

To find out the solution we set the expression =0 and solve for x

x^2 + 4x + 10=0

Apply quadratic formula to solve for x

x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

a=1, b=4, c=10 plug in the values in the formula

x=\frac{-4+-\sqrt{4^2-4(1)(10)}}{2a}

x=\frac{-4+-\sqrt{-24}}{2(1)}

The value of square root (-1) is 'i'

x=\frac{-4+-2i\sqrt{6}}{2}

Divide each term by 2

x=2+-i\sqrt{6}

sattari [20]3 years ago
3 0
X^2+4x+10=0

x^2+4x=-10

x^2+4x+4=-6

(x+2)^2=-6

x+2=±i√6

x=-2±i√6

So the correct answer is the third one down from the top.
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To solve our questions, we are going to use the kinematic equation for distance: d=vt
where
d is distance 
v is speed  
t is time 

1. Let v_{w} be the speed of the wind, t_{w} be time of the westward trip, and t_{e} the time of the eastward trip. We know from our problem that the distance between the cities is 2,400 miles, so d=2400. We also know that the speed of the plane is 450 mi/hr, so v=450. Now we can use our equation the relate the unknown quantities with the quantities that we know:

<span>Going westward:
The plane is flying against the wind, so we need to subtract the speed of the wind form the speed of the plane:
</span>d=vt
2400=(450-v_{w})t_{w}

Going eastward:
The plane is flying with the wind, so we need to add the speed of the wind to the speed of the plane:
d=vt
2400=(450+v_{w})t_{e}

We can conclude that you should complete the chart as follows:
Going westward -Distance: 2400 Rate:450-v_w Time:t_w
Going eastward -Distance: 2400 Rate:450+v_w Time:t_e

2. Notice that we already have to equations:
Going westward: 2400=(450-v_{w})t_{w} equation(1)
Going eastward: 2400=(450+v_{w})t_{e} equation (2)

Let t_{t} be the time of the round trip. We know from our problem that the round trip takes 11 hours, so t_{t}=11, but we also know that the time round trip is the time of the westward trip plus the time of the eastward trip, so t_{t}=t_w+t_e. Using this equation we can express t_w in terms of t_e:
t_{t}=t_w+t_e
11=t_w+t_e equation
t_w=11-t_e equation (3)
Now, we can replace equation (3) in equation (1) to create a system of equations with two unknowns: 
2400=(450-v_{w})t_{w}
2400=(450-v_{w})(11-t_e) 

We can conclude that the system of equations that represent the situation if the round trip takes 11 hours is:
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

3. Lets solve our system of equations to find the speed of the wind: 
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

Step 1. Solve for t_{e} in equation (2)
2400=(450+v_{w})t_{e}
t_{e}= \frac{2400}{450+v_{w}} equation (3)

Step 2. Replace equation (3) in equation (1) and solve for v_w:
2400=(450-v_{w})(11-t_e)
2400=(450-v_{w})(11-\frac{2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{4950+11v_w-2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{255011v_w}{450+v_{w}} )
2400= \frac{1147500+4950v_w-2550v_w-11(v_w)^2}{450+v_{w}}
2400(450+v_{w})=1147500+2400v_w-11(v_w)^2
1080000+2400v_w=1147500+2400v_w-11(v_w)^2
(11v_w)^2-67500=0
11(v_w)^2=67500
(v_w)^2= \frac{67500}{11}
v_w= \sqrt{\frac{67500}{11}}
v_w=78

We can conclude that the speed of the wind is 78 mi/hr.
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a point on a perpendicular bisector is 7cm from each endpoint of the bisected segment and 5cm from the point of intersection. Wh
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9514 1404 393

Answer:

  about 9.80 cm

Step-by-step explanation:

The length of half the segment (h) can be found from the Pythagorean theorem:

  h² +5² = 7²

  h² = 7² -5² = 49 -25 = 24

  h = √24 = 2√6

This is half the segment length, so the whole segment length is ...

  L = 2h = 2(2√6)

  L = 4√6 ≈ 9.7980

The length of the segment is 4√6 ≈ 9.80 cm.

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Answer:

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Step-by-step explanation:

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What is the domain of the function (-1,1) (0,0) (1,2)
galben [10]

Answer:

{-1,0,1}

Step-by-step explanation:

The domain of a function is the set of all input values. The input values are the first coordinate in any coordinate pair (x,y).

So the domain here is {-1, 0, 1}.

8 0
3 years ago
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