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lys-0071 [83]
3 years ago
12

Solve -3/4(8k-24)>-12

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

-\dfrac{3}{4}(8k-24) > -12\ \ \ \ |\teext{change the signs}\\\\\dfrac{3}{4}(8k-24) < 12\ \ \ \ |\cdot\dfrac{4}{3}\\\\8k-24 < 12\cdot\dfrac{4}{3}\\\\8k-24 < 4\cdot4\\\\8k-24 < 16\ \ \ \ |+24\\\\8k < 40\ \ \ \ |:8\\\\k < 5\to k\in(-\infty;\ 5)

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Answer:

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3 years ago
What is 1/5 times 10x?
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2x

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$6.90 :)


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5 0
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5 0
3 years ago
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Setler79 [48]

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Suppose that x=1   x+1= 1+1=2   and x+2=1+2=3   However, you need specific consecutive numbers whose sum is 57.  Remember that sum means to add:

x+  (x+1)  + (x+2) = 57                 Addition of all 3 consecutive numbers   Now solve for x

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Check your answer:  18+19+20=57                 57=57  Check

7 0
3 years ago
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