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lys-0071 [83]
3 years ago
12

Solve -3/4(8k-24)>-12

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

-\dfrac{3}{4}(8k-24) > -12\ \ \ \ |\teext{change the signs}\\\\\dfrac{3}{4}(8k-24) < 12\ \ \ \ |\cdot\dfrac{4}{3}\\\\8k-24 < 12\cdot\dfrac{4}{3}\\\\8k-24 < 4\cdot4\\\\8k-24 < 16\ \ \ \ |+24\\\\8k < 40\ \ \ \ |:8\\\\k < 5\to k\in(-\infty;\ 5)

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1)When adding two negative numbers, _________ the absolute value of the numbers and keep the negative sign.
butalik [34]


1) add.

for example -1 + -2 = - (||-1| + |-2||), which is -(1+2) or -3


2) subtract

for example 4 + -7 = -(||-7| + |4||), which is - |7 - 4| or -3


3) change
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Answer:

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