Answer:
a
Step-by-step explanation:
Answer:
the solution is x = 2 and y = 4 OR (2,4)
Step-by-step explanation:
From the question
Equation 1: 3x-2y= -2
Equation 2: 3x + y = 10
Subtract equation 1 from equation 2, that is
3x + y = 10 - (3x -2y = -2)
You get
3x - 3x + y - (-2y) = 10 - (-2)
0 + y + 2y = 10 + 2
3y = 12
Divide both sides by 3
∴ y = 12/3
y = 4
Substitute the value of y into equation 2 to get x
3x + y = 10
3x + 4 = 10
Then,
3x = 10 - 4
3x = 6
Divide both sides by 3
∴ x = 6/3
x = 2
Hence, the solution is x = 2 and y = 4
I believe it’s D bc I went over A and it doesn’t add up
I would be 3x i think.......
X is the number
x/5=5a+4
2 digits that are odd
sum is 10
ah, we can make a bit of stuff with the last 2 hints
sum is 10 and are odd
that is
9 and 1
3 and 7
5 and 5
so our possible numbers are
91,19,37,73,55
but 55 is divsible by 5 so it is out
91,19,37,73
test each
91/5 has remainder 1
19/5 has remainder 4
37/5 has remainder 2
73/5 has remainder 3
the number is 19
