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bogdanovich [222]
2 years ago
11

" alt="4x {}^{2} + 20x + 25" align="absmiddle" class="latex-formula">
using appropriate identity factories the following​
Mathematics
1 answer:
BigorU [14]2 years ago
3 0

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's Solve ~

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 20x + 25

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 10x + 10x + 25

\qquad \sf  \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) (2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) {}^{2}

or

\sf{\qquad \sf  \dashrightarrow \: 4x² + 20x + 25 }

\sf{\qquad \sf  \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

\sf{\qquad \sf  \dashrightarrow \: (2x + 5)²}

I hope it was helpful ~

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