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bogdanovich [222]

2 years ago

11

" alt="4x {}^{2} + 20x + 25" align="absmiddle" class="latex-formula">
using appropriate identity factories the following

1 answer:

BigorU [14]2 years ago

3 0

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's Solve ~

$\qquad \sf \dashrightarrow \: 4 {x}^{2} + 20x + 25$

$\qquad \sf \dashrightarrow \: 4 {x}^{2} + 10x + 10x + 25$

$\qquad \sf \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)$

$\qquad \sf \dashrightarrow \: (2x + 5) (2x + 5)$

$\qquad \sf \dashrightarrow \: (2x + 5) {}^{2}$

or

$\sf{\qquad \sf \dashrightarrow \: 4x² + 20x + 25 }$

$\sf{\qquad \sf \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}$

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

$\sf{\qquad \sf \dashrightarrow \: (2x + 5)²}$

I hope it was helpful ~

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