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yarga [219]
3 years ago
11

Whats 4 2/5 x 1 1/2 pls help​

Mathematics
2 answers:
Veronika [31]3 years ago
8 0
The answer is that (It’s 6.6)
Leni [432]3 years ago
6 0

Answer:

33/5 or 66/10

Step-by-step explanation:

First convert 4 2/5  and 1 1/2 into a improper fraction.

4 2/5 = 22/5 ; 1 1/2 = 3/2

Then multiply

66/10

And simplify

33/5

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Tamiku [17]

Answer:

the answer is A 6.50

Step-by-step explanation:

becasue u just have to look at the line and find the one hour

4 0
3 years ago
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What is -2x+5>11 graphed out on a number line?
grin007 [14]

Step-by-step explanation:

-2x>11-5

x<6/-2

x<-3

Make sure the circle in the number line isnt coloured in!

5 0
3 years ago
In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
Dale works at a mattress store, and makes a salary plus commission. He has a $500 weekly salary and makes a 5% commission for sa
Anni [7]

Answer:

1.  \( f\circ g(x)=0.05x-150

2. \( g\circ f(x)=0.05x-3000

3. The first one represents Dale's commission

Explanation:

1. The composition of the function

                                                             \( f\circ g(x)=f(g(x)) \)    

means that you first apply the function g(x) and then f(x) on the output of g(x).

That is:

  • f(x) = 0.05x
  • g(x) = x - 3000

       f(g(x)=0.05(x - 3000)

       f(g(x))=0.05x-150

2. The composition of the function

                                                             \( g\circ f(x)=g(f(x)) \)                                                                  

means that you first apply the function f(x) and then g(x) on the output of f(x).

That is:

      g(f(x))=((0.05x)-3000)=0.05x-3000

3. Which one represents Dale's commission

To calculate Dales's commision you must subtract $3,000 from the sales, to find the sales over $3000. That is: x - 3,000, which is the function g(x).

Therefore, you first use g(x).

Then, you must multiply the output of g(x) by 0.05 to find the 5% of the sales over $3,000. That is: 0.05(g((x)) = 0.05(x - 3000) = 0.05x - 150.

Therefore, the composition that represents Dale's commission is the first one:

  f(g(x)=0.05(x - 3000)

       f(g(x))=0.05x-150

4 0
3 years ago
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