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denpristay [2]
2 years ago
8

PLEASE ANSWER ASAP PLEASE HURRY I NEED THIS PLEASE!!!!!!!!!!!ill mark brainliest A nutritionist studied the U.S. consumption of

carrots and celery and of broccoli over a 6-yr period. The nutritionist modeled
the results, in millions of pounds, with the following polynomials.
Carrots and celery: -12x3 + 106x2 - 241x + 4477
Broccoli: 14x2 -14x + 1545
In each polynomial, x = 0 corresponds to the first year in the 6-yr period. What polynomial models the total number of
pounds, in millions, of carrots, celery, and broccoli consumed in the U.S. during the 6-year period?

Mathematics
1 answer:
sukhopar [10]2 years ago
7 0

The polynomial is modeled as the total number of pounds will -12x³ + 120x² - 255x + 6022. Then the correct option is B.

<h3>What is polynomial?</h3>

A polynomial expression is an algebraic expression with variables and coefficients.

A nutritionist studied the U.S. consumption of carrots and celery and of broccoli over a 6-yr period.

The nutritionist modeled the results, in millions of pounds, with the following polynomials.

Carrots and celery: -12x³ + 106x² - 241x + 4477

Broccoli: 14x² -14x + 1545

Then the polynomial is modeled as the total number of pounds, in millions, of carrots, celery, and broccoli consumed in the U.S. during the 6-year period will be

⇒ -12x³ + 106x² - 241x + 4477 + 14x² -14x + 1545

⇒ -12x³ + 120x² - 255x + 6022

Then the correct option is B.

More about the polynomial link is given below.

brainly.com/question/17822016

#SPJ1

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Can someone please help me with my maths question​
DIA [1.3K]

Answer:

a. \  \dfrac{625 \cdot m}{27 \cdot n^{11}}

b. \  \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}

By expanding the expression, we get;

\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}

Collecting like terms gives;

\dfrac{m^{(3 + 4 - 6)}  \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}

(b) The given expression is presented as follows;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4

Therefore, we get;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n}

Collecting like terms gives;

x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )

x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

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Step-by-step explanation: 3-4 times an number-5 is 3-4n-5.

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Answer:

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Understand that the graph of an equation in two variables is the set of all its solutions plotted in the coordinate plane, often forming a curve (which could be a line).

Step-by-step explanation:

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010101102837
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