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netineya [11]
3 years ago
5

Help me to solve tan^3 2x-3tan2x+2=0

Mathematics
2 answers:
Irina18 [472]3 years ago
5 0
Here you are!!!!!!!!!

Rashid [163]3 years ago
4 0

Answer:

Step-by-step explanation:

let tan 2x=y

y³-3y+2=0

y³-y-2y+2=0

y(y²-1)-2(y-1)=0

y(y+1)(y-1)-2(y-1)=0

(y-1)[y(y+1)-2]=0

(y-1)(y²+y-2)=0

(y-1)(y²+2y-y-2)=0

(y-1)[y(y+2)-1(y+2)]=0

(y-1)(y+2)(y-1)=0

y=1,1,-2

tan 2x=1=tanπ/4=tan (nπ+π/4)=tan π/4(n+1)

2x=π/4(n+1)

x=π/8(n+1)

where n is an integer.

tan 2x=-2

2x=tan^{-1}(-2)\\x=\frac{1}{2} tan^{-1}(-2)

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3 years ago
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allochka39001 [22]

Answer:

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Step-by-step explanation:

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3 years ago
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Oksana_A [137]

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3 years ago
​ Quadrilateral ABCD ​ is inscribed in this circle.
Sunny_sXe [5.5K]

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The missing figure is attached.

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Based on this, you can identify that the angle D and the angle B are opposite and, therefore, supplementary.

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