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2 years ago

Probability and Likelihood

Mathematics

1 answer:

OleMash [197]2 years ago

8 0

Answer:

i dont understand the words of these problems

Step-by-step explanation:

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A boat leaves a dock at 3:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due east at 15 km/h a

madam [21]

Answer:

The distance is minimized 22 minutes after 3:00 pm.

Step-by-step explanation:

Let t is the time for the 2 boats after 3:00 pm, we have the distance of:

Boat 1: 20t
Boat 2: 15t and its distance to the dock is given by (15-15t)

The paths of the boats form a right triangle, in which the hypotenuse (also the distance between the two boats) is:

D = (20t)² + (15 - 15t)²

<=> dD/dt = -2(15² )( 1-t ) +2 × 20² × t

<=> dD/dt = 2 (15² + 20²) × t -2 ( 15 )² = 0

<=> t = 2 ( 15 )² : 2 (15² + 20²)

<=> t = 0.36 hours = 0.36 × 60 = 21.6 minutes ≈ 22 minutes

Therefore, the distance is minimized 22 minutes after 3:00 pm.

7 0

3 years ago

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A regular hexagon rotates counterclockwise about its center. It turns through angles greater than 0° and less than or equal to 3

Talja [164]

Answer:

Step-by-step explanation:

A regular hexagon has six side and it is rotated counterclockwise about its center.

rotation is 0° < x ≤ 360

it will map on itself at the multiples of the angle = 360 / 6 = 60°

which are 60°, 120°,180°, 240°, 300° and 360°

the number of different angles = 6

7 0

3 years ago

What is the answer for 20+30x0+1= ?

Nuetrik [128]

1 20+30 x 0 =0 + 1= 1

3 0

4 years ago

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HELP ME OUT PLS‼️ Any smart as%ses

dusya [7]

Answer:

9) shifted down 2

10) shifted right 4

11) more wider

12) more narrow

Step-by-step explanation:

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3 years ago

The position of a model train, in feet along a railroad track, is given by

miv72 [106K]

Answer:

Part a) The speed is $2.5\frac{ft}{sec}$

Part b) After 4 seconds the trains is 24 ft along the track

Part c) $t=6\ sec$

Step-by-step explanation:

we have

$s(t)=2.5t+14$

This is the equation of a line in slope intercept form

where

s(t) is the position of a model train in feet

t is the time in seconds

Part a) How fast is the train moving?

The speed of the train is equal to the slope of the linear equation so

The slope m is equal to

$m=2.5\frac{ft}{sec}$

therefore

The speed is $2.5\frac{ft}{sec}$

Part b) Where is the train after 4 seconds?

For t=4 sec

substitute the value of t in the equation and solve for s

$s(4)=2.5(4)+14=24\ ft$

therefore

After 4 seconds the trains is 24 ft along the track

Part c) When will the train be 29 feet along the track?

For s(t)=29 ft

Substitute the value of s(t) in the equation and solve for t

$29=2.5t+14$

subtract 14 both sides

$29-14=2.5t$

$15=2.5t$

Divide by 2.5 both sides

$6=t$

rewrite

$t=6\ sec$

3 0

3 years ago