Answer:
Alvin traveled 150 miles downstream and 150 miles upstream, for a total distance on the river of 300 miles.
Step-by-step explanation:
Let d represent the distance Alvin traveled in one direction on the river. Then going downstream that distance took ...
... time = distance/speed
... time downstream = d/25
and the time going upstream that same distance to his point of origin took ...
... time upstream = d/15
The total of these times is 16 hours, so we have ...
... 16 = d/25 + d/15
Multiplying by 75 gives ...
... 1200 = 3d +5d = 8d
... 1200/8 = d = 150
Alving spent 6 hours going 150 miles downstream and 10 hours going 150 miles upstream. His total river distance was 300 miles. (We cannot tell which of these numbers will be considered to be the answer to the question.)
Cos²x+2cos x+1=0
We have to do a change of variable.
cos x=t
Then, we have the next square equation.
t²+2t+1=0
We solve this square equation:
t=[-2⁺₋√(4-4)]/2=-1
if cos x=t then we have that:
cos x=-1
x=cos⁻¹ -1= π radians or 180º.
Answer: x=π (in radians) or x=180º (in degrees).
But i think
Complemantary are angles whose sum is 90 and supplementary are the ones whose sum is 180
So
Complementary of 60 is 30
And
Supplementary is 120
Pleasee tell where i m wrong but this is what i studied and i am sure its correct
<span>1) if 2 times the wind speed is increased by 2, the wind speed is still less
than 46 km/h.
=> 2x + 2 < 46
2) Twice the wind speed minus 27 is greater than 11 km/h.
=> 2x - 27 > 11
Part A: Create a compound inequality to represent the wind speed range.
(3 points)
from 2x + 2 < 46
=> 2x < 44
=> x < 22
from 2x - 27 > 11
=> 2x > 11 + 27
=> 2x > 38
=> x > 19
The set of inequalities is
2x + 2 <46
2x - 27 > 11
The solution is x < 22 and x > 19, which is:
19 < x < 22 <----- answer
Part B: Can the wind speed in this town be 20 km/h? Justify
your answer by solving the inequalities in Part A. (3 points)
Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).
Part C:
The average wind speed in another town is 23 km/h, but the actual wind
speed is within 4 km/h of the average. Write and solve an inequality to
find the range of wind speed in this town.
x ≥ 23 - 4 => x ≥ 19
x ≤ 23 + 4=> x ≤ 27
=> 19 ≤ x ≤ 27
=> [19,27]
</span>
Anything (except 0) to the 0 power is equal to 1.
8^0 = 1
(-8)^0 = 1
24781297429879741^0 = 1