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Anika [276]
2 years ago
9

What is 1/4×2/5÷1/3 as a fraction please help

Mathematics
1 answer:
Vikki [24]2 years ago
4 0

Answer:

3/10

Step-by-step explanation:

Please give brainliest!

hope this helps :)

the first step is to multiply 1/4 and 2/5

1/4 times 2/5 = 2/20

you figure this out by multiplying the numerators and denominators.

next, we solve 2/20 ÷ 1/3

we do this by taking the reciprocal of 1/3, which is 3/1, and then multiplying the fractions

2/20 times 3/1 = 6/20

6/20 = 3/10

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50 (x+ 10) = 240<br> Whats the value for x
Katen [24]

Answer:

-26/5 or -5.2

Step-by-step explanation:

First, you need to expand the parentheses:

50x+500=240

Now, subtract 500 from both sides:

50x=-260

Now, divide both sides by 50

x=-26/5=-5.2

Hope this helps!

3 0
3 years ago
Read 2 more answers
20.99 for a 42 lb-bag of dog food (im pretty sure your supposed to divide the last number to the first number example: 18.5÷11.9
ra1l [238]

Answer:

18.5÷11.99 is correct the answer is most likly option B

5 0
3 years ago
What is the Quotient of 1 and 2/3 divided by 2 and 3/5
Nostrana [21]

Answer:

  25/39

Step-by-step explanation:

For division of mixed numbers, it often works well to first convert them to improper fractions. Then the division proceeds in the usual way: "invert and multiply", or "dot, swap."

__

  1\dfrac{2}{3}\div2\dfrac{3}{5}=\dfrac{5}{3}\div\dfrac{13}{5}=\dfrac{5}{3}\cdot\dfrac{5}{13}\\\\=\dfrac{5\cdot5}{3\cdot13}=\boxed{\dfrac{25}{39}}

_____

<em>Additional comment</em>

Your graphing calculator can do this, too.

7 0
2 years ago
Distributions and Comparing Data Project
LenKa [72]

Answer:

1. The shape of the histogram created with MS Excel is approximately bell shaped and approximately evenly spread about the central (largest counts) values

The shape of the box plot created with MS Excel is approximately evenly distributed

2. The appropriate measure of central tendency for a bell shaped histogram is the mean and median, due to the approximately equal distribution about the highest frequency class

3. Part A

The 15 numbers between 1  and 20 generated by a random generator are;

1, 8, 8, 15, 4, 18, 11, 6, 17, 1, 18, 15, 10, 12, 11

The measure of center is the mean =  (1+8+8+15+4+18+11+6+17+1+18+15+10+12+11)/15 = 155/15 = 31/3

The measure of spread used is the variance, s² = 32.38

Where, \,s^2 =\dfrac{\sum \left (x_i-\bar x  \right )^{2} }{n - 1}

{\sum \left (x_i-\bar x  \right )^{2} } = 453.333

n = 15

s² = 453.\overline 3/(15 - 1) = 32.38

Part B

The measure of central tendency are the mean and the median because the size of the data (n = 15), is 75% of the population (N = 20) nd therefore the data is approximately normal and can be represented by the mean and the standard deviation

Step-by-step explanation:

4 0
3 years ago
Math is so hard man but can someone help me
nataly862011 [7]

Answer:

a

Step-by-step explanation:

7 0
3 years ago
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