Please like this I need pts
Answer:
Step-by-step explanation:
Use Pythagorean theorem.
Hypotenuse² = base² + altitude²
5) x² = 12² + 6²
= 144 + 36
x² = 180
x = √180
x = 13.42 ft
6) 25² = x² + 19²
625 = x² + 361
625 - 361 = x²
x² = 264
x = √264
x = 16.25 m
7) x² = 7² + 576
= 49 + 576
= 625
x = √625
x = 25 in
8) 2.5² = 2²+ x²
6.25 = 4 + x²
6.25 - 4 = x²
x² = 2.25
x = √2.25
x = 1.5 yd
Answer:
<em>Answer</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>correct</em><em>.</em>
I believe x=10.25 because of the pythagorean theorem.
Answer:
The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°
Step-by-step explanation:
From the above question,
We have:
Camera 1 = Angle A
Camera 2= Angle B
Camera 3 = Angle C
A = 210ft
B = 234ft
C = 260ft
We need to find Angle A( angle of camera 1) using the cosine rule
A=(B² + C² - 2BCCosA)
210² = 234² + 260² - 2 × 234 × 260 × CosA
210² = 122356 - 121680CosA
Square both sides
210² = 122356 - 121680CosA
44100 = 122356 - 121680CosA
121680CosA = 122356 - 44100
121680CosA = 78256
Cos A = 78256/121680
Cos A = 0.6431295201
A = arc cos (0.6431295201)
A = 49.974422249°
Angle A approximately = 49.97°
Using the Sine rule to find the Angle B
A/Sine A = B/Sine B
210ft/Sine 49.97° = 234ft/Sine B
210ft × Sine B = 49.97° × 234ft
Sine B =( Sine 49.97° × 234ft)/210ft
B = arc sin (0.8532172354)
Angle B = 58.56334
Approximately = 58.56°
Angle C = 180 - (49.97 + 58.56)°
Angle C = 71.47°
Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°
