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OlgaM077 [116]
2 years ago
8

Part F What is the mean absolute deviation for Doctor A’s data set on glasses? What is the mean absolute deviation for Doctor B’

s data set on glasses? Write a sentence comparing the variation of the two data sets using their mean absolute deviations.
Doctor A Doctor B
Corrective Lenses Glasses Contacts Corrective Lenses Glasses Contacts
745 643 102 763 651 112
726 634 92 736 625 111
769 670 99 735 622 113
765 658 107 759 624 135
756 636 120 748 631 117
742 624 118 756 621 135
757 641 116 765 653 112
748 655 93 761 647 114
770 649 121 768 646 122
738 629 109 761 646 115
Mathematics
1 answer:
frez [133]2 years ago
7 0

There is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

<h3>The doctors' mean absolute deviation on glasses</h3>

The dataset of doctor A is given as:

643 634 670 658 636 624 641 655 649 629

The dataset of doctor B is given as:

651 625 622 624 631 621 653 647 646 646

Using a statistical calculator, we have:

<u>Doctor A</u>

  • Doctor A: Mean Absolute Deviation (MAD) = 11.28
  • Doctor B: Mean Absolute Deviation (MAD) = 12

Hence, the mean absolute deviation is 11.28 for Doctor A’s and 12 for Doctor B’s data set on glasses

<h3>The variation of the two data</h3>

In a dataset, the larger the mean absolute deviations value, the larger the variation.

By comparison, 12 is greater than 11.28

Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

Read more about mean absolute deviation at:

brainly.com/question/3250070

#SPJ1

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Compare\ y-3=\frac{4}{3}(x+2)\ with\ the\ standard\ form\\\\x_1=-2,\ y_1=3\ and\ m=\frac{4}{3}\\\\This\ is\ equation\ of\ line\ passing\ through\ (-2,3)\ and\ having\ slope(m)=\frac{4}{3}\\\\Slope=\tan \theta\\\\\tan\theta=\frac{4}{3}\\\\\theta=\tan^{-1} \frac{4}{3}\\\\\theta=53.13\textdegree\\\\Hence\ line\ passes\ through\ (-2,3)\ and\ makes\ an\ angle\ 53.13\textdegree\ with\ the\ x-axis

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