Answer:
26 bags
Step-by-step explanation:
A bag of cat chows = 30 lbs
Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow
There are at least 52 weeks in a year.
The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow
= 52 × ½
= 52/2
= 26 bags of cat chow
At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.
Answer:
Adding them together. x = 3/2, y = 8
Step-by-step explanation:
Adding because we want to get rid of a variable. If we add, 2x + 6x = 8x, 1/2 * y + (-1/2 * y) = 0, and 7 + 5 = 12. Adding gets rid of the y variable.
By adding we get that 8x = 12 which gives us x = 12/8 = 3/2
Substituting this back into either equation will give us y = 8.
I do not understand what you are asking but I am going to assume that you are trying to simplify the equation.
First, write the equation.
(4/3)b + 2 = 4 - (1/3)b
Add (1/3)b to each side.
(5/3)b + 2 = 4
Subtract 2 on each side.
(5/3)b = 2
Divide by (5/3) on each side
b = 1.2
b = 1.2 is your final answer.
Answer:
x < 4
Step-by-step explanation:
Step 1: Write inequality
5x < 20
Step 2: Solve for <em>x</em>
- Divide both sides by 5: x < 4
Here we see that any number less than 4 will work. So numbers like 3, 0, or even -12587235897 would work.
The equation -21t - 4 = 10 - 2t has only one solution
<u>Solution:</u>
Given, equation is – 21t – 4 = 10 – 2t
We have to find how many solutions does the above given equation have
Now, let us solve the given equation to find the number of solutions it has.
Then, - 21t – 4 = 10 – 2t
Taking like terms to one side of the equation we get,
- 21t + 2t = 10 + 4
here we can see only one value of t.
Hence, the given equation has only one solution.
