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Marta_Voda [28]
2 years ago
10

Please Help I Don't Understand!

Mathematics
1 answer:
Nutka1998 [239]2 years ago
4 0

The value of x is 8 from the diagram given.

<h3>How do you calculate the sides of similar triangles?</h3>

The corresponding sides of a similar triangle are said to be in proportion if and only if the corresponding angle are also equal.

To calculate the side of line x (|x|), we have to determine the ratios of the corresponding sides as:

\mathbf{\dfrac{BC}{DC} = \dfrac{AC}{EC}}

\mathbf{\dfrac{x}{10} = \dfrac{12}{15}}

x = 120/15

x = 8

Therefore, we can conclude that the value of x is 8.

Learn more about calculating similar triangles here:
brainly.com/question/11899908

#SPJ1

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Which choice is the solution?
kifflom [539]
The solution for your answer is 12

8 0
3 years ago
Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the
Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

\text{Distance}=\text{Speed}\times\text{Time}

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

\Rightarrow6x+18+6x = 162

\Rightarrow12x=162-18

\Rightarrow x=\frac{144}{12}\rightarrow x=12

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be x+3=12+3=15 \text{ mph}

8 0
2 years ago
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
Solution q-2r=4<br> q+r=37
GenaCL600 [577]
Q-2r=4, therefore: q=4+2r.

Plug the value of q into q+r=37, so you get:

4+2r+r=37

3r=37-4=33

3r=33

Therefore: r=11.

q-2r=4, but r=11, so:

q-2(11)=4

q-22=4

Therefore q=26.

Check if the answer is correct using second equation:

q=4+2r=4+2(11)=4+22=26.

So: q=26 and r=11.


4 0
3 years ago
Read 2 more answers
Can you help me please?
wel
The correct answer is true because the number do not repeat
3 0
3 years ago
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