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Digiron [165]
2 years ago
9

EXERCISE

Computers and Technology
1 answer:
nirvana33 [79]2 years ago
8 0

Answer:

1. True

2. True

3. False

4. True

5. True

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Which setting is used to determine the order of printing pages?
sineoko [7]

Answer:

Collation Settings

Explanation:

In Microsoft Word, we are given several setting options (e.g. Collation, Orientation, Margin and Scaling) to print our documents. Collation is one of the given settings that allows us to adjust the order of printing pages. There are only two options in Collation Setting (Collated or Uncollated). If Collated is chosen, the pages will be printed in sequential order (e.g. Page 1, Page 2 and Page 2) and followed by another copy of pages with same sequential order. On another hand, if Uncollated is chosen, All copies of Page 1 will be printed first then only followed by the Page 2 for all copies and so on.

7 0
4 years ago
what program searches the Internet for specified keywords and returns a list of the pages where the keywords were found
Andrews [41]

google does that, and yahoo, and bing. it would be a search engine, or browser.

5 0
3 years ago
create a new Java application called "CheckString" (without the quotation marks) according to the following guidelines.** Each m
jok3333 [9.3K]

Answer:

The Java code is given below

Explanation:

import java.io.*;

import java.util.Scanner;

import java.util.ArrayList;

public class StringCheck{

//There are several implementation approaches. This is one example framework/outline which might be helpful. Please feel free to try other approaches.

public static void checkWord(String word) throws Exception {

// Uses charAt method to test if the first letter of string variable word

// is a character. If not, throw new exception

if(Character.isLetter(word.charAt(0))){

 return;

}else{

 throw new Exception("This is not a word");

}

}

public static String getWord() {

// Declare a local scanner

// Prompt the user to enter a word

// Think about using a loop to give the user multiple opportunities to correctly enter a string

// Read into a string

// Call checkWord method passing the string as a parameter

// checkWord can throw an exception; call checkWord in a try/catch block

// Return the string to main if a valid string

Scanner sc = new Scanner(System.in);

boolean st = true;

String word = null;

while(st){

 System.out.println("Enter a Word : ");

 word = sc.next();

 try{

  checkWord(word);

  st = false;

 }catch(Exception e){

  System.out.println(e);

  st = true;

 }

}

sc.close();

return word;

}

public static void writeFile(String[] arrayToWrite, String filename) throws IOException {

// Example using FileWriter but PrintWriter could be used instead

// Create a FileWriter object

FileWriter fileWordStream = new FileWriter(filename);

// Use a loop to write string elements in arrayToWrite to fileWordStream

for(int i = 0;i<arrayToWrite.length;i++){

fileWordStream.write(arrayToWrite[i]+System.lineSeparator());

}

fileWordStream.flush();

fileWordStream.close();

// In the loop use the lineSeparator method to put each string on its own line

}

public static ArrayList readFile(String filename) throws FileNotFoundException, IOException {

// Declare local ArrayList

ArrayList<String> words = new ArrayList<>();

// Create a new File object using filename parameter

File file = new File(filename);

// Check if the file exists, if not throw a new exception

if(!file.exists()){

 throw new FileNotFoundException("File not Found");

}

// Create a new BufferedReader object      

Scanner fsc = new Scanner(file);

// use a loop and the readLine method to read each string (on its own line) from the file

while(fsc.hasNextLine()){

words.add(fsc.nextLine());

}

fsc.close();

// return the filled ArrayList to main

return words;

}

public static void main(String[] args) {

// create a string with literal values to write to the file

String[] testData = {"cat", "dog", "rabbit"};

// Create an ArrayList for reading the file

ArrayList<String> words = new ArrayList<>();

// Declare a string variable containing the file name "data.txt"

String file = "data.txt";

// Call getWord, assign the returned string to a variable and display it

String word = getWord();

System.out.println("The word is : "+word);

// Call writeFile and readFile methods in a try block

try{

writeFile(testData,file);

words = readFile(file);

// Printout the contents of the ArrayList after the call to readFile

for(int i = 0;i<words.size();i++){

 System.out.println(words.get(i));

}

}catch(FileNotFoundException e){

System.out.println(e);

}catch(IOException e){

System.out.println("IOException: error occured in input output");

}

// catch two types of exceptions

}

}

4 0
3 years ago
The address of the last cell of a memory RAM is 3FFFFh.a total capacity of the main memory and 4M bits and the data bus can tran
marysya [2.9K]

Hey there!:

Given the address of the last cell of a memory RAM is 3FFFFh then   :

There are 8 bits in a byte  

1024 bytes in a kilobyte  

 so 8*1024= 8192  

 so 8192 bits in a kb  

 32*8192 = 262144  

there are 262144 bits in 32KB .

a) 32 bit address registers must match 2^32 byte = 4 GB of physical memory.

However, with 32 Bit you can also address more than 4 GB, like Physical Address Extension (PAE) does.

The other way is that you can access 4 GB with less than 32 bit address register.

____________________________________________________

b) Main Memory = 4M × 32Kbits, RAM chips = 32K × 4bit.

For this memory we require 4 × 2 = 8 RAM chips.

Each chip requires 18 address bits (ie. 218 = 256K).

And 1M × 8 bits requires 20 address bits (ie. 220 = 1M )

_____________________________________________________

c) The size of the storage cells is known as the word size for the computer.

In some computers, the word size is one byte while in other computers the word size is two, four, or even eight bytes. In our 4M main memory the size of cell is 4*2^20 bytes.

Each storage cell in main memory has a particular address which the computer can use for storing or retrieving data.  

______________________________________________________

d) The size of MBR is the 4M bits of main memory.

_____________________________________________________

Hope this helps!

6 0
3 years ago
Type the correct answer in the box. Spell all words correctly.
Feliz [49]

Answer:

While trying to minimize project cost, project manager Ben realized that adjusting the schedule is not completely serving the purpose. What else can ben do to minimize project cost?

In addition to adjusting the schedule, Ben can adjust Everything. For example, the Ben can hire people on contract to reduce costs

7 0
3 years ago
Read 2 more answers
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