y = 3/2x + b
Plug in the point (2,2) and solve for b.
2 = (3/2)(2) + b
2 = 3 + b
b = -1
Final equation is y = 3/2x - 1.
Let h = the number of horses in the field
Let c = number of cows in the field
There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)
There are 15 animals in the field. Therefore
h + c = 15 (2)
Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15
Answer:
The correct equation is
2h - 2 = 15
Answer:
m=28
n=21
Step-by-step explanation:
3×4=12
7×4=28
28×1.75=49
12×1.75=21
I got the factors of 40 but both numbers do not add up to 11. Negative numbers are not considered because the product and sum are positive numbers.
1 x 40 = 40 1 + 40 = 41
2 x 20 = 40 2 + 20 = 22
4 x 10 = 40 4 + 10 = 14
5 x 8 = 40 5 + 8 = 13
I also got the addends of 11 and solved each set to get the product
1 + 10 = 11 1 x 10 = 10
2 + 9 = 11 2 x 9 = 18
3 + 8 = 11 3 x 8 = 24
4 + 7 = 11 4 x 7 = 28
5 + 6 = 11 5 x 6 = 30