Numbers that are divisible by 2 4 6 8 and 10 have to be?
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The question describes a binomial probability with p(h) = p, then p(t) = 1 - p and number of trials (n) = 20
The probability of a binomial distribution is given by
Part A:
The probability of observing 8 heads and 12 tails is given by:
Part B:
<span>You observe more than 8 heads and more than 8 tails, when you observe 9 heads and 11 tails, 10 heads and 10 tails, and 11 heads and 9 tails.
Therefore, the probability of </span><span>observing more than 8 heads and more than 8 tails</span> is given by:
The probability of a binomial distribution is given by
Part A:
The probability of observing 8 heads and 12 tails is given by:
Part B:
<span>You observe more than 8 heads and more than 8 tails, when you observe 9 heads and 11 tails, 10 heads and 10 tails, and 11 heads and 9 tails.
Therefore, the probability of </span><span>observing more than 8 heads and more than 8 tails</span> is given by: