Question

Consider the circle represented by this equation.

Answer 1

Answer:

See below

Step-by-step explanation:

arrange to standard form   (x-h)^2   + (y-k)^2 = r^2     h,k = center   r = radius

x^2 - 4x        +    y^2 + 2y   =   4        complete the square for 'x' and 'y'

(x-2)^2    -  4    +    (y-1)^2  -1  = 4

(x-2)^2    +  ( y-1)^2  = 4 + 4 + 1 = 9           '9' is equal to r^2  so r = 3

center = 2,1     radius = 3