Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
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X=2
Y=4
Multiply top so y values cancel out, so multiple top by -3. Y values cancel out. You combine top and bottom equations, x=2. Plug 2 in first equation for x. Y=4
You should ender 0.5 for a half note, 0.25 for a quater note, 0.125 for a eigth note, 0.0625 for a sixteenth note.
10 year ×12 months=120 months
11150000÷120=
That is the answer, sorry I am going out can't find the answer
The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.
Step-by-step explanation:
The given is,
In ΔWXY, ∠Y=90°
XW = 53
YX = 28
WY = 45
Step:1
Ref the attachment,
Given triangle XWY is right angled triangle.
Trigonometric ratio's,
∅ 
For the given attachment, the trigonometric ratio becomes,
∅ 
.....................................(1)
Let, ∠X = ∅
Where, XY = 28
XW = 53
Equation (1) becomes,
∅ 
∅ = 0.5283
∅ = 
(0.5283)
∅ = 58.109°
Result:
The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.
