Answer:
<em>(BEFORE YOU SUBMIT IT, PLEASE READ THE WARNING)</em>
QUESTION EIGHT: 2690
QUESTION NINE: 120
QUESTION ELEVEN: 12.5
QUESTION FOURTEEN: 24
Step-by-step explanation:
<u>WARNING!! FOR QUESTIONS WITH INTEREST: I do not know if interest is good or bad (if you get money, or if you lose money. I counted interest as making money, but if you are sure it's not, contact me in the comments and I will solve it again! :)</u>
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8.
may 3rd -> july 15th = 73 days
500*0.06 = 30
30 = how much he makes in one day (so he has 530 after 1 day)
30*73 = 2190
500 + 2190 = 2690
9.
210/7 = 30
1% for 3 years = 30
1% for 1 year = 10
100% for 1 year = 1000
2000*0.06 = 120
11.
54,000*0.08 = 4320
54,000/4320 = 12.5
14.
5000*6.26% = 312.5
7500/312.5 = 24
Hope this helps... T-T
3(3x+y=3)
Distribute
9x +3y=9
Plus this
1x -3y= 2
Equals
10x=11
Answer:
The 95% confidence interval for mean compressive strength is:
![3237.3\leq \mu\leq 3282.5](https://tex.z-dn.net/?f=3237.3%5Cleq%20%5Cmu%5Cleq%203282.5)
Step-by-step explanation:
We have a sample of n=12 specimens, with sample mean=3259.9 and sample standard deviation = 35.57.
We know the population is normally distributed.
For a 95% confidence interval and df=n-1=11, the t-statistic is t=2.201.
Then, the CI can be expressed as:
![M-t*s/\sqrt{N}\leq \mu\leq M+t*s/\sqrt{N}\\\\3259.9-2.201*35.57/\sqrt{12}\leq \mu\leq 3259.9+2.201*35.57/\sqrt{12}\\\\ 3259.9-22.6\leq \mu\leq 3259.9+22.6\\\\3237.3\leq \mu\leq 3282.5](https://tex.z-dn.net/?f=M-t%2As%2F%5Csqrt%7BN%7D%5Cleq%20%5Cmu%5Cleq%20M%2Bt%2As%2F%5Csqrt%7BN%7D%5C%5C%5C%5C3259.9-2.201%2A35.57%2F%5Csqrt%7B12%7D%5Cleq%20%5Cmu%5Cleq%203259.9%2B2.201%2A35.57%2F%5Csqrt%7B12%7D%5C%5C%5C%5C%203259.9-22.6%5Cleq%20%5Cmu%5Cleq%203259.9%2B22.6%5C%5C%5C%5C3237.3%5Cleq%20%5Cmu%5Cleq%203282.5)
Answer:
93.5 feet squared
Step-by-step explanation:
l=34 feet
w=2 3/4 feet
2 3/4 also = 2.75