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Verdich [7]
3 years ago
12

A car weighs 2332 pounds. If 372 pounds of old parts are removed and replaced with 412 pounds of new parts, find new weights of

the car
Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0

Answer:

2372

Step-by-step explanation:

You would do the equation 2332-372+412

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What are the next 3 numbers in this sequence? 1,1,2,4,7,13,24,44
Bogdan [553]
81,149, 274.... adding three numbers from the last would help you

like if you take 7 = 4 + 2 +1

or 13 = 7 + 4 +2

similarly 44+24+13 = 81
              81+44 +24 = 149
              149 + 81 +44 = 274

hope you get it!

6 0
3 years ago
90 points!!
Svetllana [295]

Answer:

1) 2w + 2(3w) \leq 112

2) 850w > 300w + 7500

3) The greatest age that Sue could be is 7.

4) The smaller of the two integers is 92.

5) Don needs to earn at least 244 points in the fourth game.

Step-by-step explanation:

1) An rectangle has 2 dimensions: width(w) and length(l)

The perimeter P is:

P = 2w + 2l

The problem states that the length of a rectangle is three times its width. So l = 3w and:

P = 2w + 2(3w)

The perimeter of the rectangle is at most 112 cm. It means that the perimeter can be 112, so the equal sign enters the inequality. So

2w + 2(3w) \leq 112

2)

The problem states that he earns $850 per week in sales. His earnings is modeled by the following equation:

E = 850*w, in which w is the number of weeks.

The problem also states that he spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses. So his expenses can be modeled by the following equation

C = 300*w + 7500, in which w is also the number of weeks.

He will make a profit when his earnings are bigger than his expenses, so: When they are equal, there is no profit, so the equal sign does not enter the inequality.

E > C

850w > 300w + 7500

3)

I am going to call Jenny's age x and Sue's age y.

The problem states that Jenny is eight years older than twice her cousin Sue’s age. So

x = 8 + 2y.

The sum of their ages is less than 32, so:

x + y < 32

8 + 2y + y < 32

3y < 24

y < \frac{24}{3}

y < 8

Sue's age has to be less than 8, so the greatest age that Sue could be is 7.

4)

The sum of two consecutive integers is at least 185.

There are two integers with sum of 185, so:

x + y = 185

They are consecutive so:

x = y + 1

Replacing in the sum equation:

y + 1 + y = 185

2y = 184

y = \frac{184}{2}

y = 92

The smaller of the two integers is 92.

5)

The average is the sum of all the scores divided by the number of games. So:

225 = \frac{192 + 214 + 250 + x}{4}

656 + x = 900

x = 900 - 656

x = 244

Don needs to earn at least 244 points in the fourth game.

8 0
3 years ago
Name the intersection of plane QMW and plane RMW
Norma-Jean [14]
The answer is "C", "MW".

In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with  but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.
6 0
3 years ago
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There are 125 calories in a candy bar. There are 12 candy bars in a box. How many calories are in each box of candy bars?
Andrei [34K]

Answer:

1500

Step-by-step explanation:

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3 years ago
FREE BRAINLIEST
Anvisha [2.4K]

Answer: All circles have a 360 degree so it think its A. All circles have exactly one center point.

Step-by-step explanation:

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2 years ago
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