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DedPeter [7]
2 years ago
8

If 5.37 grams of sucrose, c12h22o11, are dissolved in 21.2 grams of water, what will be the boiling point of the resulting solut

ion? (kb for water = 0.512 oc/m).
SAT
1 answer:
WARRIOR [948]2 years ago
3 0

Answer:

c

Explanation:

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Those are the maths needed

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If there are 12 x 1023 oxygens in a sample of water, how many grams of hydrogen are in the sample?.
AveGali [126]

The amount of grams of hydrogen that are in the water sample is;

3.985 g

<h3>Avogadro's number</h3>

We are given that;

Number of moles of oxygen in a sample of water = 12 × 10²³

  • Now, the chemical formula of a molecule of water is H₂O. This means that for every 1 atom or molecule of oxygen, there must be 2 hydrogen atoms or molecules present.

Since Number of moles of oxygen in the sample is 12 × 10²³, then number of moles of hydrogen will be twice that = 2 × 12 × 10²³ = 24 × 10²³ moles

Now, molar mass of hydrogen is 1 g/mol and we know that;

Molar mass = Avogadro's number(6.023 × 10²³) moles

Thus;

6.023 × 10²³ moles = 1 g/mol

Thus; 24 × 10²³ moles of hydrogen = ( 24 × 10²³ × 1)/(6.023 × 10²³)

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Read more on Avogadro's number at; brainly.com/question/914267

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