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Rom4ik [11]
1 year ago
7

Help- and also show the work please-

Mathematics
1 answer:
svetlana [45]1 year ago
8 0

A fraction is a way to describe a part of a whole.  The correct option is C.

<h3>What is a Fraction?</h3>

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

A proper fraction is a fraction whose numerator is smaller than the denominator. When a proper fraction is raised to a positive exponent greater than 1, then the product decreases but does not reach 0.

Hence, the correct option is C.

Learn more about Fraction:

brainly.com/question/1301963

#SPJ1

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If sin just answer the please lol i don't feel like typing<br><br> ASAP
yaroslaw [1]

Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

  • Quadrant 1: Both positive.
  • Quadrant 2: Sine positive, cosine negative.
  • Quadrant 3: Both negative.
  • Quadrant 4: Sine negative, cosine positive.

Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

#SPJ1

5 0
1 year ago
What is 3 divided by 0.05?
lilavasa [31]

Answer:

The answer is 60

6 0
2 years ago
Read 2 more answers
For which function is the following always true?
Ainat [17]

Answer:

i think ur right or letter b butu not c

Step-by-step explanation:

4 0
3 years ago
Yall help me?please and thank you
aksik [14]
It would be 27/8 = 3 3/8 next 18/5 = 3 3/5 after that 19/6 = 3 1/6 lastly 35/4 = 8 3/4
Hope this helped!

3 0
2 years ago
What is the equation of the line that passes through the points (15, 9) and (Negative 2, 9)? y =
Bad White [126]

\bf (\stackrel{x_1}{15}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{15}}}\implies \cfrac{0}{-17}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{0}(x-\stackrel{x_1}{15})\implies y-9=0\implies y=9

3 0
3 years ago
Read 2 more answers
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