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mojhsa [17]
3 years ago
10

I need to simplify this

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0
Hi there!

3 \sqrt{54} + 2 \sqrt{24} =
First we split up the square root into two parts.

3 \times \sqrt{9} \times \sqrt{6} + 2 \times \sqrt{4} \times \sqrt{6} =
Now we calculate the value of the square roots which have an integer as a solution

3 \times 3 \times \sqrt{6} + 2 \times 2 \times \sqrt{6} =
Multiplying the integers gives us our next step.

9 \sqrt{6} + 4 \sqrt{6} =
And finally we add up the roots.

13 \sqrt{6}
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Simplify the expression -2(y-1)+3(y+2)
romanna [79]

Answer:  y+8

Step-by-step explanation:

-2(y-1)+3(y+2)

-2y+2+3y+6

y+8

6 0
3 years ago
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)A mule deer can run one over four of a mile in 25 seconds. At this rate, which expression can be used to determine how fast a m
makvit [3.9K]
Well, if you take x to be 25 seconds, there are 2.4x in 1min. So, that multiplied by 60, would be 144x. Therefore, 1/4 multiplied by 144x should be the answer.
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3.5/5.0 =_____/15.0<br> How to solve this ?
mote1985 [20]

Step-by-step explanation:

divide 3.5 by 5.0 (3.5 ÷ 5.0 = 0.7), then multiply 0.7 by 15.0 (0.7 × 15.0 = 10.5), and check by dividing (10.5 ÷ 15.0 = 7.0) the answer is 10.5

6 0
3 years ago
Siri am I a mix of recipe that calls for 1 1/2 cups of flour and 3/4 to get butter Jeremiah uses three sticks of butter how many
Inga [223]

Answer:

6 cups

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jeremiah 4× the recipe

3/4×4=3

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8 0
3 years ago
In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha
olga55 [171]

In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid  meteor:

1 + \frac{1}{5}  \\ \\ = 1 + 0.2 \\  \\ = 1.2

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

x = \frac{525600}{1.2}

x = 438000

∴  438,000 meteors fell during the Perseid shower.

For  Leonid meteor shower:

4 + \frac{2}{3} = 4.67

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that  fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0
3 years ago
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