Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.
What is a Dominant Trait?
A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.
Given the following traits:
A - attached earlobes (dominant allele)
a - unattached earlobes (recessive allele)
A cross between Aa and aa is shown in the image attached below.
The offspring having attached earlobes = 2 Aa = 50%.
50% of the osspring will have attached earlobes.
Learn more about dominant trait on:
brainly.com/question/16616523
Answer:
221
Step-by-step explanation:
2 - 1 + 5 · 4 · 11 = 2 - 1 + 20 · 11 = 2 - 1 + 220
2 - 1 + 220 = 1 + 220
You can probably look up a answer key for that worksheet. ;)
The correct answer is 8 1/3. Hope this helps!!
