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Rzqust [24]
2 years ago
10

Please help me!! High School algebra 2 math. Big Ideas Math

Mathematics
2 answers:
nikklg [1K]2 years ago
6 0

Answer:

x = 8

Step-by-step explanation:

The interior angles of a triangle sum to 180°.

The given triangle is a <u>right triangle</u>, so the missing angle is 45°

⇒ 180° - 90° - 45° = 45°

As the triangle has <u>2 equal angles</u>, this means it is an <u>isosceles triangle</u> (with its vertex at the right angle).  An isosceles triangle has <u>legs of equal measure</u>, therefore x=8.

<u>Proof</u>

This can be proven by using the tan trigonometric ratio to calculate the value of x.

<u>Tan trig ratio</u>

\sf tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = 45°
  • O = 8
  • A = x

Substituting the given values into the equation and solving for x:

\implies \tan (45^{\circ})=\dfrac{8}{x}

\implies x=\dfrac{8}{\tan (45^{\circ})}

\implies x=\dfrac{8}{1}

\implies x=8

krok68 [10]2 years ago
4 0

Answer:

x = 8

Step-by-step explanation:

Hello!

The missing angle in the triangle can be found by subtracting 90° and 45° from 180°. The missing angle is 45°.

This means that the triangle is isosceles, as there are two congruent base angles, 45° and 45°.

The side lengths opposite these two angles are congruent.

We can see that 8 is opposite 45°, and x is opposite 45°. Therefore, x must be equal to 8.

The value of x is 8.

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Read 2 more answers
Suppose that the functions p and q are defined as follows.
Brut [27]
<h2>Answer:</h2>

Answer:

(r o q)(-1) = 20

(q o r)(-1) = -11

Step-by-step explanation:

Given

q(x) = -2x + 1q(x)=−2x+1

r(x) = 2x^2 + 2r(x)=2x2+2

Solving (a): (r o q)(-1)

In function:

(r o q)(x) = r(q(x))

So, first we calculate q(-1)

q(x) = -2x + 1q(x)=−2x+1

q(-1) = -2(-1) + 1q(−1)=−2(−1)+1

q(-1) = 2 + 1q(−1)=2+1

q(-1) = 3q(−1)=3

Next, we calculate r(q(-1))

Substitute 3 for q(-1)in r(q(-1))

r(q(-1)) = r(3)

This gives:

r(x) = 2x^2 + 2r(x)=2x2+2

r(3) = 2(3)^2 + 2r(3)=2(3)2+2

r(-1) = 2*9 + 2r(−1)=2∗9+2

r(-1) = 20r(−1)=20

Hence:

(r o q)(-1) = 20

Solving (b): (q o r)(-1)

So, first we calculate r(-1)

r(x) = 2x^2 + 2r(x)=2x2+2

r(-1) = 2(-1)^2 + 2r(−1)=2(−1)2+2

r(-1) = 2*1 + 2r(−1)=2∗1+2

\begin{gathered}r(-1) = 6\\\end{gathered}r(−1)=6

Next, we calculate r(q(-1))

Substitute 6 for r(-1)in q(r(-1))

q(r(-1)) = q(6)

q(x) = -2x + 1q(x)=−2x+1

q(6) = -2(6) + 1q(6)=−2(6)+1

q(6) =- 12 + 1q(6)=−12+1

q(6) = -11q(6)=−11

Hence:

(q o r)(-1) = -11

8 0
3 years ago
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