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3 years ago

The area of a circular field is 16π square miles. What is the diameter of the field in miles.

Mathematics

2 answers:

Galina-37 [17]3 years ago

4 0

Answer:

8 miles

Step-by-step explanation:

When given area, we use the formula of 2√(area/pi). It may look slightly complex, but in this equation, we are fortunate that pi is in our area. This essentially cancels out the pi in the equation, simplifying it to √(16), which is simply 8!

Hope this helps you!

ella [17]3 years ago

3 0

Answer:

Step-by-step explanation:

1. Divide the area (in square units) by Pi (approximately 3.14159).

2. Take the square root of the result. This is the radius.

3. Now double the radius to get the diameter

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What is 48 times 3 I'm giving y'all an easy chance for points answer is 144 I think

ch4aika [34]

Answer:

yup you are correct. The answer is 144 :)

Step-by-step explanation:

Also thx for the points!

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3 years ago

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Please help!!! Which equation is in point-slope form and is depicted by the line in this graph?

Blizzard [7]

Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m

so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so

points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)

so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer

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4 years ago

Caroline drove 350 miles to her grandmother’s house. The trip took her 5 1/4 hours. What was her average speed in miles per hour

Shalnov [3]

64 hours per hour average
350 miles ÷5.25 hours in which it took= 63.63 rounded is 64 mph average

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3 years ago

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saul85 [17]

Answer= $185.00

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3 years ago

What is the equation of the line that passes through the points (-1, 7) and (2, 10) in Standard Form?

Usimov [2.4K]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{10-7}{2-(-1)}\implies \cfrac{3}{2+1}\implies \cfrac{3}{3}\implies 1$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}$

just to point something out, is none of the options, however -x + y = 8, is one, though improper.

3 0

3 years ago