Answer: I think its 2.09
Step-by-step explanation:
But i'm not sure.
Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Answer:
(a) 0.0128 to 4 decimal places
(b) The 90% confidence interval is 119.1 < μ < 121.0 to 1 decimal places
Step-by-step explanation:
See the attached documents and graphs. Cheers!
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I'm assuming the the numbers coming after the variables are meant to be exponents, and if I'm wrong just let me know
-3x^4 - 2x^3 + 3x^2 + 3x^4 - 4x^3 + x^2, rearrange to have like terms in order
-3x^4 +3x^4 - 2x^3 - 4x^3 +3x^2 + x^2, now simplify
0 -6x^3 + 4x^2
Answer:
As far as i know you should go for LCM that would be more convenient and easy to do