Answer:Get the equation in the form y = ax2 + bx + c.
Calculate -b / 2a. This is the x-coordinate of the vertex.
To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.
Step-by-step explanation:
Answer:
A: The interquartile range is 8.
Step-by-step explanation:
Hopefully this helps!
The equation of the line would be
y = mx+b
where m is the slope, b is the y intercept.
<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept
and the base is y intercept divided by slope. Therefore,</span>
A = b^2/2m
At point (2,5)
5 = 2m+b
Substitute that in the area
A = b^2/5-b
to find the least area, differentiate the area with respect to the height and equate it to 0
dA/db = 0
<span>find b and
use that to find m. Then, you can have the equation of the line.</span>
Answer:
I believe it's the first one
Answer:
222
Step-by-step explanation:
42/3 x 111/4 = (42 x 111)/(3 x 4)
42/3 x 111/4 = 2664/12
42/3 x 111/4 = 222
