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2 years ago

Solve this equation 3x-1/5-2/9x=124/5

Mathematics

1 answer:

Flauer [41]2 years ago

7 0

Answer: x = 9

Step-by-step explanation:

1) Combine multiplied terms into a single fraction

2) Find a common denominator

3) Combine fractions with common denominator

4) Multiply from left to right (PEMDAS)

5) Multiply all terms by the same value to eliminate fraction denominators

6) Cancel multiplied terms that are in the denominator

7) Multiply again

8) Add _ to both sides

9) Divide both sides by the same factor getting 125x/125 = 1125/125

10) Simplify, x = 9

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Step-by-step explanation:

The n th term I obtained in your previous question, that is

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4 years ago

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2 years ago

Let c be the path c(t) = (2t, t2, log(t)), defined for t > 0. find the arc length of c between the points (2, 1, 0) and (12,

V125BC [204]

The path starts at $t=1$ and ends at $t=6$ , so we have an arc length of

$\displaystyle\int_{\mathcal C}\mathrm dS=\int_{t=1}^{t=6}\|\mathbf c'(t)\|\,\mathrm dt$
$=\displaystyle\int_1^6\sqrt{2^2+(2t)^2+\left(\frac1t\right)^2}\,\mathrm dt$
$=\displaystyle\int_1^6\sqrt{4t^2+4+\frac1{t^2}}\,\mathrm dt$
$=\displaystyle\int_1^6\frac1t\sqrt{4t^4+4t^2+1}\,\mathrm dt$
$=\displaystyle\int_1^6\frac1t\sqrt{(2t^2+1)^2}\,\mathrm dt$
$=\displaystyle\int_1^6\frac{2t^2+1}t\,\mathrm dt$
$=\displaystyle\int_1^6\left(2t+\frac1t\right)\,\mathrm dt$
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4 years ago