Answer:
x = 12 hrs to fill the pool
Step-by-step explanation: INCOMPLETE QUESTION
Missed information:
Time for two different sizes hoses to fill a small simming pool (let say that is 3 hours)
Time for one of the two hoses to fill a small simming pool ( lt say that is 4 hours)
With that information we can answer the question
If one of the hoses fill the pool in 4 hours, it will fill 1/4 of the pool in 1 hour
We dont know the other hose how long it take to fill the pool so let call that time x hours then in 1 hour it will fill 1/x of the pool
In 1 Hour the two hoses will fill 1/3 of the pool then
In one hour
1/4 + 1/x = 1/3 Solving for x
( x + 4 )/ 4x = 1/3
3x + 12 = 4x
- x = -12 x = 12 hours
16*16*4 . 16*4
solvong it
X squared +14=9x
Square both sides and you get
X+14=3x subtract 14 from both sides
Z
X=3x-14 subtract 3x
-2x=-14 divide negative 2
X=7
The answer to the problem is as follows:
<span>Well isn't the range of y=cos(u) is [-1,1]
So the max value for y=cos(u) is 1
And the min value for y=cos(u) is -1
--
So the max value for f(x)=4cos(u) is:
</span>
<span>f(u)=4cos(u)
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
