Question

Find the equation of the line passing through the points -2x+1 (8,2)

Answer 1

The line that passes through (-2, 1) and (8, 2) is:

y = (1/10)*x + 12/10

How to find the equation of the line?

I assume you want to find the equation of the line that passes through (-2, 1) and (8, 2).

A general linear equation is written as:

y = a*x + b

If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope can be written as:

$a = \frac{y_2 - y_1}{x_2 - x_1}$

In this case, we know that it passes through (-2, 1) and (8, 2), then:

$a = \frac{2 - 1}{8 - (-2)} = 1/10$

Then the line is:

y = (1/10)*x + b

To find the value of b, we use one of the given points, for example if we use (8, 2), it means that when x = 8, we must have y = 2.

2 = (1/10)*8 + b

2 - 8/10  = b

20/10 - 8/10 = b

12/10 = b

Then the linear equation is:

y = (1/10)*x + 12/10

If you want to learn more about linear equations:

brainly.com/question/1884491

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