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Nataly_w [17]
1 year ago
11

Rewrite using exponential notation \root(6)((4\pi )^(3))

Mathematics
1 answer:
Nezavi [6.7K]1 year ago
5 0

~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt[6]{(4\pi )^3}\implies (4\pi )^{\frac{3}{6}}\implies (4\pi )^{\frac{1}{2}}

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What is the greatest common factor (gcf) of the numerator and denominator in the rational expression below? 7x+14/2x^2+x-6
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4 0
3 years ago
What are the total amount of choices possible if an individual is to create a 4 digit password using the digits 0 through 9 incl
qwelly [4]

9000 ways to create 4-digit passwords using digits from 0 to 9 that the first character can't be 0, but not using the digit 0 as the first character.

We have to see how many different 4-digit passwords we can create by using digits from 0 to 9, such that the first character can't be 0.

<h3>What is the combination?</h3>

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

Here we have 4 selections.

Now let's find the number of options for each of these:

First character = 9 options {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Second character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Third character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Fourth character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

The total number of different combinations is just the product of these 4 numbers:

C = 9×10×10×10 = 9,000

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If you want to learn more about combinations visit here;

brainly.com/question/2280026

4 0
2 years ago
Read 2 more answers
The graph below shows the solution set of which inequality ?
Anestetic [448]

Answer:

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5 0
2 years ago
Multiply 3/7 by the reciprocal of -3/14​
Alexandra [31]

Multiplying 3/7 by the reciprocal of -3/14,

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Hope it helps!!

7 0
2 years ago
Help me solve this please .
lord [1]

x = 59

3x - 33 = 2x + 26

-2x -2x

1x - 33 = 26

+33 +33

1x = 59

----- -----

1 1

x = 59

4 0
3 years ago
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