Answer: The mean increases.
Step-by-step explanation:
The value of 0.9 mg/L is very low compared to a means of 7.6 mg/L with a standard deviation of 2.1 mg/L. It seems as though it is an outlier that is suffiently different from the others, and probably should be dropped from the data set. That would do 2 things: 1) the stabdard deviation will likely decrease, indicating a more confident data set, and 2) the mean vitamin C level will increase.
Answer:
X= -10
Step-by-step explanation:
<span>Simplifying
3a2 + -2a + -1 = 0
Reorder the terms:
-1 + -2a + 3a2 = 0
Solving
-1 + -2a + 3a2 = 0
Solving for variable 'a'.
Factor a trinomial.
(-1 + -3a)(1 + -1a) = 0
Subproblem 1Set the factor '(-1 + -3a)' equal to zero and attempt to solve:
Simplifying
-1 + -3a = 0
Solving
-1 + -3a = 0
Move all terms containing a to the left, all other terms to the right.
Add '1' to each side of the equation.
-1 + 1 + -3a = 0 + 1
Combine like terms: -1 + 1 = 0
0 + -3a = 0 + 1
-3a = 0 + 1
Combine like terms: 0 + 1 = 1
-3a = 1
Divide each side by '-3'.
a = -0.3333333333
Simplifying
a = -0.3333333333
Subproblem 2Set the factor '(1 + -1a)' equal to zero and attempt to solve:
Simplifying
1 + -1a = 0
Solving
1 + -1a = 0
Move all terms containing a to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1a = 0 + -1
Combine like terms: 1 + -1 = 0
0 + -1a = 0 + -1
-1a = 0 + -1
Combine like terms: 0 + -1 = -1
-1a = -1
Divide each side by '-1'.
a = 1
Simplifying
a = 1Solutiona = {-0.3333333333, 1}</span>
OK so you take the 5 miles in one hour and divide that by 2 to find the half hour
x=5/2 x= 2.5 miles
To find the 2 1/2 hours you take the hour distance (5) double it and add the half hour distance
x=(5 x 2) + 2.5 x= 10 + 2.5 x=12.5 miles
