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2 years ago

What is the measure of angle ACB

Mathematics

1 answer:

zubka84 [21]2 years ago

7 0

Answer:

Angle ACB: 28
Arc AB: 56

Explanation:
- To find AB, the angle of BOA is a central angle. And its according arc is AB. The angle is always the same as the arc as long if its a central angle.

- Angle ACB is an inscribed angle. Its according arc is AB. Whenever its an inscribed angle, its half of its arc.
56 / 2 = 28

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Need help ASAP!! I'll give brainliest to whoever answers correctly!!!

jolli1 [7]

Answer:

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3 years ago

The striton family had a meal catered for a wedding rehearsal dinner.the cost of the dinner was 476.there was a 5% sales tax and

Leokris [45]

476.00×5%=23.80 tax=476+23.80=499.80
499.80×15%=74.97
499.80+74.97=574.77

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3 years ago

What is the answer to ((1+3+6+9)-10)

Daniel [21]

Hey there! :)

((1 + 3 + 6 + 9)) - 10)

Start in the first set of parenthesis.

(19) - 10)

Simplify!

Our answer is 9 - hope I helped! :)

6 0

3 years ago

Please need help on this

artcher [175]

Answer:

the center is (-4,7) and the radius is 3

Step-by-step explanation:

The center of a circle can be found using the equation $(x-h)^2 + (y-k)^2 = r^2$ and is (h,k) from it. Notice h and k are the opposite value as in the equation.

First write the equation in this form.

$x^2 + 8x + ( ?)+ y^2 - 14y + (?) + 56 = 0$

Complete the square with each variable to find what numbers should go in place of the question marks.

$(8/2)^2 = 4^2 = 16$

$(-14/2)^2 = -7^2 = 49$

Add 16 and 49 to both sides of the equation.

$x^2 + 8x + 16 + y^2 - 14y + 49 + 56 = 16 + 49\\(x+4)^2 + (y-7)^2 + 56 = 65\\(x+4)^2 + (y-7)^2 = 9$

So the center is (-4,7) and the radius is 3.

5 0

3 years ago

How are percent transmittance and absorbance related algebraically?

statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:

A ∝ b · c

As Transmittance, $T =\dfrac{P}{P_0}$

% Transmittance, $\%T=100\times T$

Absorbance,

$A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T$

Hence, $A=\log_{10}\times \dfrac{1}{T}$ is the algebraic relation between absorbance and transmittance.

8 0

2 years ago