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Vladimir [108]
2 years ago
13

A sample of 4 different calculators is randomly selected from a group

Mathematics
1 answer:
REY [17]2 years ago
7 0

\displaystyle\\|\Omega|=\binom{72}{4}=\dfrac{72!}{4!68!}=\dfrac{69\cdot70\cdot71\cdot72}{2\cdot3\cdot4}=1028790\\|A|=\binom{46}{4}=\dfrac{46!}{4!42!}=\dfrac{43\cdot44\cdot45\cdot46}{2\cdot3\cdot4}=163185\\\\P(A)=\dfrac{163185}{1028790}=\dfrac{473}{2982}\approx0.1586

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Find the side lengths in the following triangle.
faltersainse [42]

Answer:

I'm not too sure which one you need, so choose what answer needs to go in the box!

JL= 44.5

JK=23.3

KL=23.3

Step-by-step explanation:

Since JK and KL are equal to eachother, we have to find the missing variable through them. You want to choose one side to have the variable number and the other side for the normal numbers. I can't really explain this next bit, so I'll show the math below:

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8 0
3 years ago
(4*10^2)(2*10^5) written in scientific notation
Akimi4 [234]
<span>(4*10^2)(2*10^5)
= 8 x 10^7

hope it helps</span>
8 0
4 years ago
Read 2 more answers
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