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2 years ago

What angle has a tangent and sine that are both negative? 300 210 45 150

Mathematics

1 answer:

zimovet [89]2 years ago

6 0

Answer:

$300^{\circ}$

Step-by-step explanation:

$\text{In quadrant IV, both ratios of tangent and sine are negative.}\\ \\300^{\circ}~ \text{lies in the fourth quadrant, so}~ \tan 300^{\circ} ~ \text{and}~ \sin 300^{\circ}~ \text{are negative.}$

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Julian has to read 4 articles for school. He has 8 nights to read them. He decides to read the same number of articles each nigh

daser333 [38]

Answer:

a. He will have to read half an article per night

b. Fraction of the reading assignment read each night = $\frac{0.5}{4}=\frac{1}{8}$

Explanation:

Part a:

We are given that:

number of articles to read = 4 articles

number of nights = 8 nights

To get the number of articles that he should read per night, we will simply divide the the number of articles by the number of nights

Therefore:

number of articles to read per night = $\frac{4}{8}=\frac{1}{2}$ articles per night

Part b:

Now, we know that he will read half an article each night from a total of 4 articles

To get the fraction of the reading assignment read each night, we will divide the number of articles read each night by the total number of assignments

Therefore:

Fraction of the reading assignment read each night = $\frac{0.5}{4}=\frac{1}{8}$

Hope this helps :)

5 0

3 years ago

If (x) = x+8 and g(x) = -4x-3, find (f+ g)(x).

Ede4ka [16]

Answer:

Answer=B

(f+g)(x)=-3x-5

Step-by-step explanation:

f(x)=x+8.

g(x)=-4x-3.

(f+g)(x) means f(x)+g(x),So

(x+8)+(-4x-3)

(add all same terms together)

=(x+(-4x))+(8+(-3))

=-3x+5

so,

(f+g)(x)=-3x+5

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3 years ago

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3 years ago

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chubhunter [2.5K]

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3 years ago

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