Answer:
Determine whether a relation represents a function.
Find function values.
Determine whether a function is one-to-one.
Use the vertical line test to identify functions.
Graph the functions in the library of functions.
Step-by-step explanation:
Answer:
0.60
Step-by-step explanation:
Probability that the customer is not a poor risk = 1 - probability that the customer is a poor risk
Firstly, let’s calculate the probability of being a poor risk.
From the given data the number of poor risks = 14229-7362-1190 = 5677
So the probability of being a poor risk = 5677/14229 = 0.399
Thus, the probability that the customer is not a poor risk = 1-0.399 = 0.601 which to 2 decimal places = 0.60
i mean ig but 129.... ehh
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = 
= 5.29
