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worty [1.4K]
2 years ago
12

Set A= 1, 3, 4, 5, 9, 10, 11 Set B= 2, 4, 6, 7, 11, 12 What is the union of sets A and B?

Mathematics
2 answers:
sergij07 [2.7K]2 years ago
6 0

Answer:

1 ,2,3,4,5,6,7,9,10,11,12 is the union

spin [16.1K]2 years ago
3 0

Answer:

A U B = {1,2,3,4,5,6,7,9,10,11,12}

Step-by-step explanation:

Union of sets is a set containing all elements that are in A or  B.

A = {1,3,4,5,9,10,11}

B= {2,4,6,7,11,12}

A U B = {1,2,3,4,5,6,7,9,10,11,12}

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A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

   = 59.43

B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
2 years ago
Express the ratio in lowest form:<br>1.5 kg: 350 g​
irakobra [83]

Given:

The ratio is:

1.5 kg : 350 g​

To find:

The lowest or simplest form of the given ratio.

Solution:

We know that,

1 kg = 1000 g

We have,

1.5 kg : 350 g​

It can be written as

1.5\ kg : 350\ g=\dfrac{1.5\ kg}{350\ g}

1.5\ kg : 350\ g=\dfrac{1.5\times 1000\ g}{350\ g}

1.5\ kg : 350\ g=\dfrac{1500\ g}{350\ g}

1.5\ kg : 350\ g=\dfrac{150}{35}

1.5\ kg : 350\ g=\dfrac{30}{7}

Therefore, the lowest form of the given ratio is 30:7.

5 0
3 years ago
Need an answer, please need an answer, please​
dusya [7]

Answer:

Step-by-step explanation:

1) 6  and -5

x₁ + x₂  = 6 +(-5) = 1

x₁* x₂   = 6*(-5) = -30

x² -(x₁ + x₂)x + (x₁* x₂)=0

x² - x  - 30 = 0

2) 4 and 7

x₁ + x₂  =4 + 7 = 11

x₁* x₂   = 4*7 = 28

x² - 11x + 28 = 0

3) 1 and -10

x₁ + x₂  = 1 +(-10) = -9

x₁* x₂   = 1*(-10) = -10

x²  - 9x - 10 = 0

4) -9 and 0

x₁ + x₂  = -9 + 0 = -9

x₁* x₂   = 0

x² - (-9)x  = 0

x² + 9x = 0

5)2 and 6

x₁ + x₂  = 2 + 6 = 8

x₁* x₂   = 2*6 = 12

x² -8x + 12 = 0

8) 2 +√3  and 2 - √3

x₁ + x₂  = 2+ √3 + 2 - √3 = 4

x₁* x₂   = (2 + √3)(2 - √3) = 2² - (√3)² 4 - 3 = 1

x² - 4x + 1 = 0

7 0
3 years ago
How to factor 15m^2-12m^3
tester [92]
Step 1. Find the Greatest Common Factor (GCF)
GCF = 3m^2
Step 2. Factor out the GCF <span>(Write the GCF first. Then, in parentheses, divide each term by the GCF.)
3m^2(15m^2/3m^2 + -12m^3/3m^2)
Step 3. Simplify each term in parentheses 
3m^2(5 - 4m)</span>
8 0
4 years ago
Read 2 more answers
What are three multiples of 4/5?
sashaice [31]

do you mean the equivalent fractions?

If so,The equivalent fractions of 4/5 are 8/10, 12/15, 16/20 

I hope this is what you mean.

3 0
3 years ago
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