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sveta [45]
3 years ago
5

What is the answers of 6b and 6c?

Mathematics
1 answer:
Dimas [21]3 years ago
7 0
Hello,

6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.

So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop

The answer is 37%.

(ii) For this question, we basically have the same process as the previous question except for the second year.

From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop

The answer is 12%.

6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.

The initial value of the car is 27,000, and after 5 years the value is 8,000. 
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.

The answer is 70%.

Hope this helps!


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frez [133]
We will use the Pythagorean theorem:
8² + 12² = c² 
64 + 144 = c²
c = √208 ≈ 14.42
14.42 - 12 = 2.42 in
The direct distance between the lizard and the cactus is 2.42 inches. 
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By investing in a variety of investment options
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Roman is born in the year 123 BC and dies at the age of 74 years. Use a negative number to express the year in which he dies
Stells [14]

Answer:

-49 or 49 BC

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7 0
3 years ago
Please help me with the below question.
tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0
2 years ago
Find all the square roots of x2 ≡ 53 (mod 77)
Nikolay [14]

Answer:

x=\pm\sqrt{77n+53}

Step-by-step explanation:

We have been given an equivalence equation x^2\equiv 53\text{ (mod } 77). We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

x^2-53=77n

Add 53 on both sides:

x^2-53+53=77n+53

x^2=77n+53

Take square root of both sides:

x=\pm\sqrt{77n+53}

Therefore, the square root for our given equation would be x=\pm\sqrt{77n+53}.

3 0
3 years ago
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